64-49v^2=0

Solution for 64-49v^2=0 equation:

64-49v^2=0

a = -49; b = 0; c = +64;
Δ = b2-4ac
Δ = 02-4·(-49)·64
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-112}{2*-49}=\frac{-112}{-98}
=1+1/7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+112}{2*-49}=\frac{112}{-98}
=-1+1/7
$